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(0.56x^2)-(4.8x)+3.12=0
We add all the numbers together, and all the variables
(0.56x^2)-(+4.8x)+3.12=0
We get rid of parentheses
0.56x^2-4.8x+3.12=0
a = 0.56; b = -4.8; c = +3.12;
Δ = b2-4ac
Δ = -4.82-4·0.56·3.12
Δ = 16.0512
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.8)-\sqrt{16.0512}}{2*0.56}=\frac{4.8-\sqrt{16.0512}}{1.12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.8)+\sqrt{16.0512}}{2*0.56}=\frac{4.8+\sqrt{16.0512}}{1.12} $
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